Question

Calculate the gross calorific value of coal having following composition c=85% H=8% S=1% Nitrogen =2% ash =4% latent heat of steam 587cal /g

9650.4 kcal/g

9650.4 cal/gm

None of above

Both a and b​

Answer 1

Answer:

9650.4 cal/gm

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Answer 2

Answer:

The gross calorific value of coal ( GCV ) measured is $9650.4cal/g$.

Therefore, option b) $9650.4cal/g$ is correct.

Explanation:

Data given,

The percentage of carbon ( C ) = $85\%$

The percentage of hydrogen ( H ) = $8\%$

The percentage of sulfur ( S ) = $1\%$

The percentage of nitrogen ( N ) = $2\%$

The percentage of ash = $4\%$

The latent heat of steam = $587cal/g$

The gross calorific value of coal ( GCV ) =?

Now, we can find out the GCV by using the equation given below:

• GCV = $\frac{1}{100}\times [8080C + 34500(H-\frac{O}{8}) +2240S]kcal/kg$

Here,

• C = % of carbon = $85\%$
• H = % of hydrogen = $8\%$
• O = % of oxygen = $0\%$
• S = % of sulfur = $1\%$

After putting these values into the equation, we get:

• GCV = $\frac{1}{100}\times[ { 8080(85) + 34500(8-\frac{0}{8}) +2240(1)]kcal/kg$
• GCV = $\frac{1}{100}\times[ { 686800 + 34500(8-0) +2240]kcal/kg$
• GCV = $\frac{1}{100}\times[ { 686800 + 276000 +2240]kcal/kg$
• GCV = $\frac{1}{100}\times[ { 686800 + 276000 +2240]kcal/kg$
• GCV = $\frac{1}{100}\times[ {965040]kcal/kg$
• GCV = $9650.4kcal/kg$

As we know,

• $1kcal/kg$ = $1cal/g$

Therefore,

• $9650.4kcal/kg = 9650.4cal/g$

Hence, the gross calorific value of coal ( GCV ) measured is $9650.4cal/g$.