Question

Calculate the H° of the reaction
SiO2(s) + 3C(s) —> SiC(s) + 2CO(g)
if,
i) Si(s) + O2(g) —> SiO2(s); ∆H° = -911KJ
ii) 2C(s) + O2(g) —> 2CO(g); ∆H° = -221KJ
iii) Si(s) + C(s) —> SiC(s); ∆H° = - 65.3KJ

Class 11th Thermodynamics​

Answer 1

Answer:

+ 624.7KJ

Explanation:

reverse the first eq :

sio2 ---> si + o2 ∆H = + 911 KJ

2C + O2 ---> 2CO. ∆ H = -221 KJ

SI + C ----> SiC ∆H = -65.3 KJ

NOW ADD UP ALL THE EQUATION TO GET

SiO2 + 3CV--> SiC + 2CO

WITH THE ∆ H = + 624.7 KJ

HOPE THIS HELPS