Math, asked by niraj663, 1 year ago

if the function f(x) is continuous in [0,3] where f(x)=3x-4 for 0≤x≤2 =2x+k for 2<x≤3 find the value of constant k

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Answered by brunoconti
0

Answer:

Step-by-step explanation:

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Answered by mkrishnan
1

Answer:

Step-by-step explanation:

if the function f(x) is continuous in [0,3]

Then   the function f(x) is continuous  at x= 2 also

limit at x=2    is    value at x=2

\lim_{x \to \ 2+}f(x) = f[2]\\ \lim_{x\to\ 2+} 2x+k = 3[2]-4

2[2] + k = 6 - 4

         4+k = 2

            k = 2-4 = -2

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