Question

Calculate the heat developed when 3 ampere current flowing through an

eletcric iron box designed to work under 230 volt for 5 minutes.​

Answer 1

Answer:

The heat developed is 207000J = 207KJ

Explanation:

V = 230V I = 3A t = 5 minutes = 300s

V = IR

R = V/I

R = 230/3

H = i^2Rt

H = 3 ^2 × 230/3 × 300

H = 9 × 230/3 × 300

H = 207000J