Calculate the heat developed when 3 ampere current flowing through an
eletcric iron box designed to work under 230 volt for 5 minutes.
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Answer:
The heat developed is 207000J = 207KJ
Explanation:
V = 230V I = 3A t = 5 minutes = 300s
V = IR
R = V/I
R = 230/3
H = i^2Rt
H = 3 ^2 × 230/3 × 300
H = 9 × 230/3 × 300
H = 207000J
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