calculate the heat energy received by 5m square Area on the earth surface in 1 minute resuming that 47% of the Solar Energy strike the Earth surface ?
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hey mate^_^
here is your answer!!
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solar heat energy received= Solar constant × area × time
47% of solar constant × area × time
(47/ 100) ( 1.4kw/ m^2 ) (5M^2) ( 1×60s)
= 197.4 kJ
be brainly
here is your answer!!
_____________________________________
solar heat energy received= Solar constant × area × time
47% of solar constant × area × time
(47/ 100) ( 1.4kw/ m^2 ) (5M^2) ( 1×60s)
= 197.4 kJ
be brainly
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