Question

calculate the heat energy required to raise the temperature of 2 kilogram of water from 10 ⁰c to 50 ⁰c. C of water 4200 J/kg/K

Answer 1

$\sf \Large Solution!!$

$\sf \to m=2\:kg$

$\sf \to c=4200\:J\:kg^{-1}\:K^{-1}$

$\sf \to ∆t=50°C-10°C=40°C=40\:K$

$\sf$

$\sf Q=mc∆t$

$\sf Q=2\:\cancel{kg}\times 4200\:J\:\cancel{kg^{-1}}\:\cancel{K^{-1}}\times 40\:\cancel{K}$

$\sf Q=336000\:J$

Q → Heat Energy

m → Mass of water

c → Specific heat capacity of water

∆t → Rise in temperature