Question

Calculate the heat, in kilocalories, that is absorbed if 182 g of ice at 0.0 ∘C is placed in an ice bag, melts, and warms to body temperature of 37.0 ∘C. The heat of fusion for water is 80. cal/g, or 334 J/g. The specific heat for water is 1.00 cal/g∘C, or 4.184 J/g∘C.​

Answer 1

Answer:

Heat absorb =mL+mc×(T−0)

so , 182 × 80 + 182 × 1 × 37 = 2194 J

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