calculate the heat of combustion of ethene?
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ch3ch2oh +o2 = co2+h2o
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C2H4+3O2--------- 2CO2+2H2O
Heat of combustion= bond energy of reactants - bond energy of products.
So, (4×414+619+3×499) - (4×724+4×460) = -964kJ/mol
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