Question

please solve...... simultaneous equation

Answer 1

(1) 2x +1/7 + 5y - 3/3 = 12

     3(2x + 1) + 7(5y - 3) = 21 * 12

     6x + 3 + 35y - 21 = 252

     6x + 35y - 18 = 252

     6x + 35y = 252 + 18

     6x + 35y = 270   

      6x = 270 - 35y

       x = 270 - 35y/6 -------------------- (1)


(2) 3x + 2/2 - 4y+3/9 = 13

     9(3x + 2) - 2(4y + 3) = 13 * 18

     27x + 18 - 8y - 6 = 234

     27x - 8y + 12 = 234

     27x - 8y = 234 - 12

     27x - 8y = 222    --------------- (2)

    Substitute (1) in (2), we get  

27(270 - 35y/6 - 8y = 222

9(270 - 35y)/2 - 8y = 222

9(270 - 35y) - 16y = 444

2430 - 315y  - 16y = 444

-331y = -1986

y = 1986/331

y = 6    ------------------------------------ (3)


Substitute (3) in (2), we get

27x - 8y = 222

27x - 8 * 6 = 222

27x - 48 = 222

27x = 222 + 48

27x = 270

x = 270/27

x = 10.


Therefore the value of x = 10 & y = 6.


Hope this helps!

Answer 2

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