Question

calculate the height of water column which will exerts on its base the same pressure as the 0.70 m of mercury column. density of hg is 13.6×10³kg/m³​

Answer 1

Answer:

Pressure will remain same for both the liquids.

Hence, Pressure = ρ×g×h

ρ = density of the liquid

g = acceleration due to gravity

h = height of the column

⟹ρ

mercury

×g×h

mercury

=ρ

water

×g×h

water

⟹ρ

mercury

×h

mercury

=ρ

water

×h

water

Given, ρ

mercury

=13.6 h

mercury

=70

ρ

water

=1 h

water

=?

Hence,

h

water

=

1

13.6×70

h

water

=952cm

Explanation:

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