Question

calculate the internal energy change of a system when 10kj of work is done on the system and 2kj of heat is given out by the system​

Answer 1

Answer:

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The internal energy change of a system is 10kJ

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Explanation:

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According to the first law of thermodynamics:

 Δ∪ = q + w

Δ∪ =Change in internal energy

q = heat absorbed or released

w = work done on or by the system

w = work done by the system= PΔV  {Work is done by the system is negative as the final volume is greater than initial volume }  

w = - 10 kJ

q = +20 kJ   {Heat absorbed by the system is positive}

  Δ∪ = (+20) +  (-10)

= 10kJ

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