Calculate the ionisation energy of rubidium per atom, if light of wavelength 5.84 108 m produces electrons with a speed of 2.450 106 ms1 .
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E = energy in the light rays
= h ν = h c /λ
= 6.67 * 10×⁻³⁴ * 3 * 10⁸ / (5.84*10⁻⁸) J
= 3.42 * 10⁻18 J
Kinetic energy of electrons
= 1/2 m u^2
= 1/2 * 9.1 * 10⁻³¹ * (2.45 * 10⁶)² J
= 2.73 * 10⁻¹⁸ J
The ionization energy = (3.42 - 2.73) * 10⁻¹⁸ J
= 6.9 * 10⁻¹⁹ J
= h ν = h c /λ
= 6.67 * 10×⁻³⁴ * 3 * 10⁸ / (5.84*10⁻⁸) J
= 3.42 * 10⁻18 J
Kinetic energy of electrons
= 1/2 m u^2
= 1/2 * 9.1 * 10⁻³¹ * (2.45 * 10⁶)² J
= 2.73 * 10⁻¹⁸ J
The ionization energy = (3.42 - 2.73) * 10⁻¹⁸ J
= 6.9 * 10⁻¹⁹ J
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