Question

Calculate the K. E of 6 moles of nitrogen at 25 °c

Answer 1

$\blue{\underline{ \huge{ \blue{\boxed{ \mathfrak{\fcolorbox{red}{orange}{\purple{Answer}}}}}}}}$

• Given :

Moles of nitrogen = 6

Temperature = 25+273 = 298 K

• To Find :

Kinetic energy of nitrogen gas

• Formula :

Average kinetic energy of gas molecules is given as...

$\: \: \: \: \: \boxed{ \green{ \bold{ \huge{ \rm{KE = \frac{3}{2} nK{ \tiny{b}}T}}}}}$

Where Kb = boltzman constant

• Calculation :

$\rm \: </strong><strong>K</strong><strong>E</strong><strong> = \frac{3}{2} \times 6 \times 1.38 \times {10}^{ - 23} \times 298 \\ \\ \star \: \boxed{ \rm{ \pink{</strong><strong>K</strong><strong>E</strong><strong> = 3.7 \times {10}^{ - 20} \: </strong><strong>J</strong><strong>}}}$