Calculate the kinetic energy of a body of mass 0.1 kg and momentum 20kg ms ^-1.
Answers
Required answer:–
Given:-
• Momentum (p) = 20kg ms^-1
• Mass of body = 0.1kg
To find:-
• Calculate the kinetic energy
As we know:
• p = mv
Where:
• p = momentum
• k = kinetic energy
• v = velocity
• m = mass
Step by step explaination:-
Now using the value of v in the given equation....
That is,
Now substituting the values....
That is,
Answer:
2 × 10³ J
Extra information:
• The energy possessed by a body due to its state of motion is called the kinetic energy.
• The kinetic energy possessed by a moving body is equal to the amount of work which the moving body can do before coming to rest.
• Kinetic energy depends upon square of its velocity of motion.
• A faster moving body has more kinetic energy than a slowly moving body
Answer:
Required answer:–
Given:-
• Momentum (p) = 20kg ms^-1
• Mass of body = 0.1kg
To find:-
• Calculate the kinetic energy
As we know:
• \: K \: = \dfrac{1}{2} mv {}^{2}•K=
2
1
mv
2
• p = mv
• \: v \: = \dfrac{p}{m}•v=
m
p
Where:
• p = momentum
• k = kinetic energy
• v = velocity
• m = mass
Step by step explaination:-
Now using the value of v in the given equation....
That is,
\bold\blue{k \: = \dfrac{1}{2}m \times ( \dfrac{p}{m}) {}^{2} = \: \dfrac{p {}^{2} }{2m} }k=
2
1
m×(
m
p
)
2
=
2m
p
2
Now substituting the values....
That is,
\bold\blue{ \dfrac{20 {}^{2} }{2 \times 0.1} }
2×0.1
20
2
\bold\blue{ \dfrac{20 \times 20}{2 \times 0.1} }
2×0.1
20×20
\bold\blue{2000J}2000J
\bold\blue{2 \times 10 {}^{3}J}2×10
3
J
Answer:
2 × 10³ J
Extra information:
• The energy possessed by a body due to its state of motion is called the kinetic energy.
• The kinetic energy possessed by a moving body is equal to the amount of work which the moving body can do before coming to rest.
• Kinetic energy depends upon square of its velocity of motion.
• A faster moving body has more kinetic energy than a slowly moving body
Explanation:
Hope it helps you
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