Question

calculate the kinetic energy of a bullet of mass 0.05 kg fired from a gun and travelling with a speed of 100m/s​

Answer 1

Answer:hope this answer help you

Explanation:

Momentum is conserved, so use:

M1V1 + M2V2 = M1V1f + M2V2f

if the bullet comes out at half of 300m/s, it is traveling at 150m/s. That is the V1f.

You have everything else, just solve for V2f. So...

(.01)(300) + (1)(0) = (.01)(150) + (1)(V2f)

3 = 1.5 + V2f

V2f= 1.5 m/s

So A

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