Question

Calculate the length of a second's pendulum at a place where acceleration due to gravity is 9.8

m/s².​

Answer 1

Given :

Acceleration due to gravity = 9.8m/s²

To Find :

Length of second pendulum.

Solution :

❖ Time period of a simple pendulum in terms of length of pendulum and acceleration due to gravity is given by

$\dag\:\underline{\boxed{\bf{\orange{T=2\pi\sqrt{\dfrac{L}{g}}}}}}$

» T denotes time period

» L denotes length

» g denotes acceleration

We know that time period of second pendulum is 2s.

By substituting the given values;

$\sf:\implies\:T=2\pi\sqrt{\dfrac{L}{g}}$

$\sf:\implies\:2=2(3.14)\sqrt{\dfrac{L}{9.8}}$

$\sf:\implies\:\dfrac{2}{6.28}=\sqrt{\dfrac{L}{9.8}}$

$\sf:\implies\:\dfrac{L}{9.8}=(0.318)^2$

$\sf:\implies\:L=0.101\times 9.8$

$:\implies\:\underline{\boxed{\bf{\purple{L=0.99\:m}}}}$

Knowledge BoosteR :

• Second pendulum is the simple pendulum, having a time period of 2 second. Its effective length is 99.992 cm or approximate one metre on earth.
• The motion of a simple pendulum is simple harmonic for small angular displacement.

Answer 2

Answer:

Question :-

Calculate the length of a second's pendulum at a place where acceleration due to gravity is 9.8

Calculate the length of a second's pendulum at a place where acceleration due to gravity is 9.8 m/s².

Solution :-

⟹

$l = 0.99m$

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