Calculate the length of a seconds pendulum at a place where g= 10m/s²
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Answered by
4
Answer:
Explanation:
Time period of seconds pendulum = 2 s
T = 2 π sqrt(L / g)
L = [T^2 g / (2 π)^2]
= [(2^2 * 10) / (2 π)^2]
= 1.0 m
Length of the seconds pendulum is 1.0 m
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Answered by
7
Explanation:
it is so simple by using formula and remember that the time period of seconds pendulum is 2 sec in any part of globe
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