Question

calculate the length of hypotenuse in the following figure​

Answer 1

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Angle A = 60°

Perpendicular = √3

Hypotenuse = ?

$\frac{hypotenuse}{perpendicular} = \csc(60)$

$\frac{hypotenuse}{ \sqrt{3} } = \frac{2}{ \sqrt{3} }$

$hypotenuse = \frac{2}{ \sqrt{3} } \times \sqrt{3}$

$hypotenuse = \frac{2}{ \sqrt{3} } \times \frac{ \sqrt{3} \times \sqrt{3} }{ \sqrt{3} }$

$hypotenuse = \frac{2(3)}{3} = \frac{6}{3}$

Thus, Hypotenuse = 2

Hope this helps you❤️