Question

calculate the length of the dna of bacteriophage lambda that has 48502 base pairs

Answer 1

use the formula,
no. of bp= (length of DNA )/0.34×10^-9 .
here length is taken in meters.

Answer 2

Distance between two pairs=0.34nm=0.34×10^-9m/bp
Therefore,total number of base pairs given are 48502
Total length of DNA=0.34×10^-9m/bp×48502=16490.68×10^-9 or 16.49×10^-6m