Question

calculate the linear velocity of the tip of a second switch of length 0.02 metre.​

Answer 1

Answer:

the linear velocity of the second's switch is 0.21 cm/s

Explanation:

Length of the seconds hand = 0.02 m

Since in 60 seconds the second's hand completes one full revolution

Therefore the distance covered in 1 second = $2\pi r$

r is the radius which is equal to the length of the second's hand = 0.02 m

Therefore, distance covered in 60 seconds

$=2\times\pi\times 0.02$

$=2\times 3.14\times 0.02$

$=0.1256$ m

Speed = Distance/Time

Speed of the second's hand

$=\frac{0.1256}{60}$

$=2.09\times10^{-3}$ m/s

$=0.21$ cm/s

Therefore the linear velocity of the second's switch is 0.21 cm/s

Hope this answer is helpful.

Answer 2

Answer:

0.002m/s

Explanation: