Question

Calculate the longest and shortest wavelength for lyman series

Answer 1

Answer:

A)

For Lyman series n1=1

For shortest λ of Lyman series; energy difference in two levels showing transition should be maximum i.e n2=∞

1λ=RH[112−1∞2]

1λ=109678

λ=911.7×10−8cm

=911.7A∘

For longest λ of Lyman series; energy difference in two levels showing transition should be minimum i.e n2=2

1λ=RH[112−122]

=109678×34

λ=1215.67×10−8cm

=1215.67A∘

Answer 2

Answer:

For Lyman series n1=1

For shortest λ of Lyman series; energy difference in two levels showing transition should be maximum i.e n2=∞

1λ=RH[112−1∞2]

1λ=109678

λ=911.7×10−8cm

=911.7A∘

For longest λ of Lyman series; energy difference in two levels showing transition should be minimum i.e n2=2

1λ=RH[112−122]

=109678×34

λ=1215.67×10−8cm

=1215.67A∘

Explanation: