Chemistry, asked by vidhi111, 1 year ago

Calculate the longest wavelength transition in lyman series


rohitpatil11598: wavelength maximum for Lyman series=4/3R

Answers

Answered by Sangun
1

Calculate the wave number for the longest wavelength transition...

For the Balmer series, n i = 2.
Thus, the expression of wavenumber is given by,
Wave number is inversely proportional to wavelength of transition.
Hence, for the longest wavelength transition, has to be the smallest.
For to be minimum, n f should be minimum.
= 1.5236 × 106 m–1

Hope it helps
Please mark as brainliest
#SANGUN


Sangun: Pleased to help you
Sangun: Mark as brainliest please.
Answered by Anonymous
0

Answer:

Calculate the wave number for the longest wavelength transition...

For the Balmer series, n i = 2.

Thus, the expression of wavenumber is given by,

Wave number is inversely proportional to wavelength of transition.

Hence, for the longest wavelength transition, has to be the smallest.

For to be minimum, n f should be minimum.

= 1.5236 × 106 m–1

Hope it helps

Please mark as brainliest

#SANGUN

Explanation:

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