Question

calculate the magnetic field at the centre of a coil in the form of a square of side 4 cm carrying a current of 5 ampere

Answer 1

Explanation:

Given calculate the magnetic field at the centre of a coil in the form of a square of side 4 cm carrying a current of 5 ampere  

• Now the coil is in the form of a square. Now this is carrying a current of 5 A in any direction.
• Now we need to find the magnetic field at the centre of the coil.
• The magnetic field will be in all directions from the centre of the coil. So the angle will be 45 degree
• So we have μo i / 4 π d [ sin theta 1 + sin theta 2]
•         So μo i / 4 π d [ sin 45 + sin 45]
•      So μo I / 4 π d [ 1/√2 + 1 / √2
•          10^-7 x 5 / 2 x 10^-2 [ 2 / √2 ] (now d = 4 cm is total distance but we need from the centre so 4/2 = 2]
•              = 5 / √2 x 10^-5
•             = 0.353 x 10^-4 Tesla
•         Or 0.353 Gaus s

Reference link will be

https://brainly.in/question/7396924