calculate the magnitude of an electric field due to an electric dipole of dipole moment 3.56*10^-29 at apoint 25.4nm away along the bisector axis
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Answer:
Dipole moment =4×10
−11
㎝
9=4nC each
distance between charges in dipole =d
9d=4×10
−9
×d
1
=4×10
−11
d=10
−9
m
a) At axis
E
due
to+9=
(0.02)
2
K
9
E
due
to−9=
(0.02)
2
−K
9
E
net
=K
9
[
(0.01)
2
1
−
(0.02)
2
1
]
=27×10
4
n/C
At perpendicular 0.02m
E
net
=2n
∣E
+9
∣=∣E
−9
∣ at point P
given y=0.02
E
netP
=2∣E∣cosθ
=
⎝
⎛
(
2
d
)
2
+y
2
⎠
⎞
2㎏
⋅
⎝
⎛
y
2
+(
2
d
)
2
⎠
⎞
y
=
⎝
⎛
(
2
0.01
)
2
+(0.02)
2
⎠
⎞
2×9×10
9
×4×10
−9
⋅
⎝
⎛
(0.02)
2
+(
2
0.01
)
2
⎠
⎞
0.02
=
(4.25×10
−4
)
3/2
8
=9.13×10
5
N/C
Explanation:
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