Question

Calculate the magnitude of force exerted by each rocket (T). The initial acceleration is 45 m/s2, the mass of the system is 3000 kg, and the force of friction opposing the motion is known to be 630 N.

Answer 1

Given :

Acceleration of rocket = 45m/s²

Mass = 3000kg

Force of friction = 630N

To Find :

Force exerted by rocket.

Solution :

■ As per newton's second law of motion, force is measured as the product of mass and acceleration.

• It is a polar vector quantity having both magnitude as well as direction.
• SI unit : N

✵ Force of friction is also acting in this case so we need to find net force first.

✵ Net force acting on the rocket will be equal to the product of mass and acceleration.

$:\implies\tt\:F_{rocket}-F_{friction}=m\times a$

$:\implies\tt\:F_{rocket}-630=3000\times 45$

$:\implies\tt\:F_{rocket}-630=135,000$

$:\implies\tt\:F_{rocket}=135,000+630$

$:\implies\:\underline{\boxed{\bf{\orange{F_{rocket}=135,630\:N}}}}$