calculate the magnitude of force required to stop a car moving with a velocity of 30 M per second in 10 seconds the mass of the car is 1500 kg
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Answered by
24
u= 30m/s. t = 10sec. v = 0
a = v-u/t
a = -30/10
a = -3m/s^2
F = MA
F = 1500*(-3)
f = -4500N
ie. we have to apply -4500N force to stop the car in opposite direction
a = v-u/t
a = -30/10
a = -3m/s^2
F = MA
F = 1500*(-3)
f = -4500N
ie. we have to apply -4500N force to stop the car in opposite direction
Answered by
11
-4500N it is -ve as acting against the motion and opposing it
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