calculate the magnitude of pressure that will be created if a force of 90 newto. is applied to an area measuring 0.09 square metre?
Answers
given that force=90Nforce=90N and area=0.09m^{2}area=0.09m2
given that force=90Nforce=90N and area=0.09m^{2}area=0.09m2FORMULA: pressure=pressure= \frac{force}{area}areaforce
given that force=90Nforce=90N and area=0.09m^{2}area=0.09m2FORMULA: pressure=pressure= \frac{force}{area}areaforce \begin{gathered}=\frac{90}{0.09} \\\\=\frac{9000}{9}\\=1000\frac{N}{m^{2} } \\\end{gathered}=0.0990=99000=1000m2N
given that force=90Nforce=90N and area=0.09m^{2}area=0.09m2FORMULA: pressure=pressure= \frac{force}{area}areaforce \begin{gathered}=\frac{90}{0.09} \\\\=\frac{9000}{9}\\=1000\frac{N}{m^{2} } \\\end{gathered}=0.0990=99000=1000m2N
given that force=90Nforce=90N and area=0.09m^{2}area=0.09m2FORMULA: pressure=pressure= \frac{force}{area}areaforce \begin{gathered}=\frac{90}{0.09} \\\\=\frac{9000}{9}\\=1000\frac{N}{m^{2} } \\\end{gathered}=0.0990=99000=1000m2N ANSWER: 1000N/m^{2}1000N/m2 or 1000 Paor1000Pa
given that force=90Nforce=90N and area=0.09m^{2}area=0.09m2FORMULA: pressure=pressure= \frac{force}{area}areaforce \begin{gathered}=\frac{90}{0.09} \\\\=\frac{9000}{9}\\=1000\frac{N}{m^{2} } \\\end{gathered}=0.0990=99000=1000m2N ANSWER: 1000N/m^{2}1000N/m2 or 1000 Paor1000Pa PRESSURE:
given that force=90Nforce=90N and area=0.09m^{2}area=0.09m2FORMULA: pressure=pressure= \frac{force}{area}areaforce \begin{gathered}=\frac{90}{0.09} \\\\=\frac{9000}{9}\\=1000\frac{N}{m^{2} } \\\end{gathered}=0.0990=99000=1000m2N ANSWER: 1000N/m^{2}1000N/m2 or 1000 Paor1000Pa PRESSURE:Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is spread. Pressure is force divided by area. Using standard metric units, the basic measure of force is equal to1N/m^{2}1N/m2 . This standard unit of pressure has been defined as the Pascal, where1Pa=1N/m^{2}1Pa=1N/m2 .
SI unit of pressure: Pascal.