Question

find p(2) ,p(-2) ,if p(x) =x³+2x²-4x-8

step to step explanation
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Answer 1

If we have a function $f(x)$, then $f(y)$ simply means that we replace the values of the $x$ in $f(x)$ with $y$.

Using this knowledge we can solve the given question.

$p(x)=x^3+2x^2-4x-8$

Thus, $p(2)$ equals:

$p(2)=(2^3)+(2*2^2)-(4*2)-8\\p(2)=8+8-8-8\\p(2)=0$

And $p(-2)$ equals to:

$p(-2)=(-2)^3+2*(-2)^2-4*(-2)-8\\p(-2)=-8+8+8-8\\p(-2)=0$