Question

Calculate the magnitude of the torque required to
hold a bar magnet of magnetic moment 200 Am^2
along a direction making an angle of 30° with the
direction of a uniform magnetic field of 0.36 G​

Answer 1

Answer:

Torque experienced by a magnet suspended in a uniform magnetic field B is given by

τ=MBsinθ

Here, M=200Am^2,B=0.30NA^-1 m^-1 and θ=30°

∴τ=200×0.30×sin30°

τ=30N m

Explanation:

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Answer 2

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