calculate the mass and volume of oxygen required at STP to convert 2.4kg of graphite into carbon dioxide
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I hope it will help you
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akkalisrujan:
it is not clear
C+O2=CO2, 12gm=32gm(O2)=> 1gm = 32/12=>2400=32/12x2400=6400gm(O2), now find moles and then multiply by 22.4 to it too get volume
Answered by
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The reaction is
C+O2------------>CO2
12g of C requires 2×16th of oxygen
2400g of course requires ((2×16)/12)*2400 g
=6400 g of o2
Volume =4480litre
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