calculate the mass in gm of mg which contains the same no of atom as present in 4 gm of calcium
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Explanation:
Molar Mass of Magnesium
(
Mg
)
:
24.31 g/mol
Molar Mass of Calcium
(
Ca
)
:
40.08 g/mol
Avogadro's constant
=
6.022
⋅
10
23
particles of a substance per mol of that substance
8.0
g Ca
⋅
1
mol Ca
40.08
g Ca
⋅
6.022
⋅
10
23
atoms of Ca
1
mol Ca
=
1.2
⋅
10
23
atoms of Ca
The number of atoms of Mg should be the same as the number of atoms of Ca, so:
1.2
⋅
10
23
atoms of Mg
⋅
1
mol Mg
6.022
⋅
10
23
atoms of Mg
⋅
24.31
g Mg
1
mol Mg
=
4.9
g Mg
You can also eliminate the step of converting to atoms, as a mol of any substance contains
6.022
⋅
10
23
particles of that substance
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