Question

calculate the mass of 0.1 mole of na2co3.10h2o​

Answer 1

$\huge \text{\underline {ANSWER}}$

Mass of 0.1 mole of Na₂CO₃ · 10H₂O = 28.6 g

$\huge \text{\underline {EXPLANATION}}$

We know that,

Number of moles = Given Mass / Molar mass

In the given case,

Number of moles = 0.1 mole

Molar mass = (23*2) + (12*1) + (16*3) + (18*10)

                   = 46 + 12 + 48 + 180

                   = 286 g

Substituting these values we get,

0.1 = Given mass / 286

Given mass = 0.1 * 286

Given mass = 28.6 g