Question

Calculate the mass of 1.0505 × 10^23 molecules of carbon dioxide ?

Answer 1

it will be answer of this question

Answer 2

Answer : The mass of carbon dioxide is, 7.675 grams

Solution :

As we know that,

1 mole weighs 44 gram of carbon dioxide which contains $6.022\times 10^{23}$ number of molecules

As, $6.022\times 10^{23}$ number of molecules present in 44 grams of carbon dioxide molecule

So, $1.0505\times 10^{23}$ number of molecules present in $\frac{1.0505\times 10^{23}}{6.022\times 10^{23}}\times 44=7.675$ grams of carbon dioxide molecule

Therefore, the mass of carbon dioxide is, 7.675 grams