calculate the mass of 1.0505×10^23molecule s of carbondioxide
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6.023×10^23=1 mole of CO2= 44gm of CO2
So, 1.0505×10^23 =0.1744 moles of CO2= 7.674 gm of CO2
So, 1.0505×10^23 =0.1744 moles of CO2= 7.674 gm of CO2
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