Question

Calculate the mass of 12.0 × 10¹⁴ atoms of hydrogen .

Answer 1

No of atoms = mole × avogadro numberMole = No of atomsAvogadro number = 12 × 10146.022 ×1023 = 1.993 × 10-9 moleMole = Given massmolar massGiven mass = mole × molar mass =1.993 × 10-9 × 1.008 = 2.009 × 10-9

Answer 2

The mass of $12.0\times 10^{14}$ atoms of hydrogen weigh $1.99\times 10^{-9}g$

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

1 mole of hydrogen $H_2$ contains=$6.022\times 10^{23}$  molecules of $H_2$

1 mole of hydrogen $H_2$ contains=$2\times 6.022\times 10^{23}=12.05\times 10^{23}$  atoms of $H_2$

$12.05\times 10^{23}$  atoms of $H_2$ weigh = 2 g

Thus $12.0\times 10^{14}$  atoms of $H_2$ weigh =$\frac{2}{12.05\times 10^{23}}\times 12.0\times 10^{14}=1.99\times 10^{-9}g$

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