Question

Calculate the mass of 12.044 ✖ 10 power 23 numbers of nitrogen molecule. please give the answer in nb If you can.

Answer 1

28gm ➡️ 6.023×10²³ molecules

So, x gm ➡️ 12.044×10²³ molecules

By cross-multiplication,

6.023×10²³ × x = 12.044×10²³ × 28

So, x = 12.044×10²³ × 28 / 6.023×10²³

x = 28 × 2

So, x = 56gm.

Answer 2

given no. of molecules = 12.044* 10²³

avogadro no = 6.022*10²³

no of moles = no of molecules / avogadro no

= 12.044 *10²³ /6.022* 10²³

= 2moles

molar mass of nitrogen = 14g

mass = molar mass * no of moles

mass = 14g*2

mass = 28g