Question

calculate the mass of 120 ml of N2 at 150 degree centigrade and 10^5 Pascal pressure

Answer 1

PV=nRT

PV=m/M×RT

m=PVM/RT

P=10^5Pa

V=120ml

T=423k(150+273)

M=28

m=PVM/RT

=10^5×120×28÷8.314×10^7×423

=0.095g

Answer 2

Given: V=120ml, T=150°C, P=$10^{5}$Pa.

To find: mass of nitrogen gas.

Step-by-step method:

Step 1 of 2

$PV=nRT\\PV=\frac{wRT}{m} \\w=\frac{PVm}{RT}$

Step 2 of 2

Substituting all the values we will get,

$w=\frac{10^{2}kPa *0.120L*28gmol^{-1}}{8.314LkPaK^{-1}mol ^{-1}*423K} \\w=\frac{33.6}{3516.82} \\w=0.0095g$

The mass of nitrogen gas will be 0.0095g.