Question

Calculate the mass of 15L of NH3 at 27°c and 900mmhg

Answer 1

Answer:

12.257g or 12.26g

Explanation:

let us cnvrt

c to k

mmhh to atm

k=c+273=27+273=300k

1atm=760mmhg

900mmhg=900/760mmhg

from given things we can find no of moles of NH3

by PV=nRT

900/760×15=n×0.0821×300

17.763=24.63n

n=0.721mol

n=mass/molar mass

0.721=mass/17

mass = 17×0.721=12.257g

which is approx = 12.26g