Two forces of 4N and 6N are inclined at an angle of 60° with each other . Find the magnitude and direction of resultant vecrors.
Answers
Answer:
, P and Q be the two forces having magnitudes 15 Newtons and 20 Newtons respectively. They are acting at an angle α = 60°.
Let, R be the resultant vector. Vector R acts at an angle θ with vector P.
So, |R^2| = 15^2 + 20^2 + 2 * 15 * 20 * cos 60°
Or, |R^2| = 225 + 400 + 300 = 925
Or, |R| = 30.4138 Newtons
So, tan θ = (20 * sin 60°) / {15 + 20 * cos 60°}
Or, tan θ = (10√3) / (15 + 10) = (10√3) / 25
Or, tan θ = (2√3) / 5 = 0.69282
Or, θ = 34.715°
So, magnitude of the resultant force = 30.4138 Newtons and the resultant force acts at an angle 34.715° with the 15 Newton magnitude force.
Explanation:
i hope this helps u
Given,
= 4N
= 6N
Angle of inclination (n) = 60°
To Find,
Magnitude and Direction of Resultant
Solution,
We know the formula for the magnitude of resultant of two vectors is
=
Substituting the given values we get,
=
=
= 8.7177 N
For Direction,
tan (n) = /
tan (n) = 6/4
tan (n) = 1.5
n = (1.5)
n =
The magnitude and direction of the resultant force are 8.718 N and 56.30 degree respectively.