Question

Calculate the mass of 6.022×10^23 molecules of NH4CL at STP?

Answer 1

Answer:

$\frac{mass}{molecular \: weight} = \frac{no}{na} \\ \frac{mass}{53.5} = \frac{6.022 \times {10}^{23} }{6.022 {10}^{23} } \\ mass \: = 53.5 \: g$

Explanation:

Answer 2

Answer:

The mass of 6.022×10²³ molecules of NH₄Cl at STP will be equal to 53.5g.

Explanation:

Given, the number of molecules of NH₄Cl = 6.022×10²³

At STP means standard temperature and pressure which is T=298K and pressure P=1atm.

Molecular mass is the sum of atomic mass of all atoms present in a molecular formula of a compound.

The molecular mass of ammonium chloride = 14+4(1)+35.5=53.5gmol⁻¹

We know that 1 mole of any compound has molecules =  6.022×10²³

Mass of 6.022×10²³ molecules of ammonium chloride = Molecular mass

Mass of 6.022×10²³ molecules of NH₄Cl  = 53.5g

Therefore, the mass of 6.022×10²³ molecules of  NH₄Cl  is equal to 53.3g.