Question

calculate the mass of 600cm^3 of nitrogen gas measure at 150°c and 750mm of mercury pressure​

Answer 1

Explanation:

The given data is as follows.

       P = 750 mm Hg = 0.986 atm        (as 1 mm Hg = 0.0013 atm)

       T = $150^{o}C$ = (150 + 273) K = 423 K

        V = 600 $cm^{3}$ = 0.6 L        (as 1 $cm^{3}$ = 0.001 L)

According to ideal gas equation, PV = nRT

As, n = $\frac{mass}{\text{molar mass}}$

Molar mass of $N_{2}$ gas is 28 g/mol. Therefore, putting given values into the above equation as follows.

                   PV = nRT

or,              PV = $\frac{mass}{\text{molar mass}}RT$

            $0.986 atm \times 0.6 L = \frac{mass}{28 g/mol} \times 0.0821 L atm/mol K \times 423 K$

                0.5916 atm L = mass × 1.24 L atm mol/g

                mass = 0.477 g

Thus, we can conclude that mass of given nitrogen gas is 0.477 g.