calculate the mass of ammonia sample which contains 3 * 10^22 atoms of nitrogen
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saurabh10021:
class 11 lesson mole concept....
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The ratio between N and H is 1:3
If N is 3*10²²
H is 9*10²²
moles of N in sample
3*10²²/6.022*10²³=0.05 Moles
mass of N in sample is 0.05*14=0.7g
moles of H in sample
9*10²²/6.022*10²³=0.15 moles
mass of H in sample is 0.15*1=0.15g
Therefore mass of NH₃ is 0.7+0.15=0.85g
Hope this helps
If N is 3*10²²
H is 9*10²²
moles of N in sample
3*10²²/6.022*10²³=0.05 Moles
mass of N in sample is 0.05*14=0.7g
moles of H in sample
9*10²²/6.022*10²³=0.15 moles
mass of H in sample is 0.15*1=0.15g
Therefore mass of NH₃ is 0.7+0.15=0.85g
Hope this helps
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