Question

Calculate the mass % of benzene (C6H6) And carbon tetrachloride (CCL4) if 22g of benzeneis dissolved in 122g of carbon tetrachloride

Answer 1

Given,

Benzene (C6H6) is 22g in the solution.

Carbon tetrachloride (CCl4) is 122g in solution

We know,

Mass Percentage of solute =

Total mass of the solution = 22g (benzene) + 122g (carbon tetrachloride)

= 144g

Mass percentage of benzene (C6H6) = 15.28%

Note: The second method to calculate the Mass percentage of carbon tetrachloride = 100 – Mass % of C6H6

= 100 - 15.28%

= 84.72%

Answer 2

Answer :

Mass of Benzene = 22 g

Mass of carbon tetrachloride = 122 g

Mass percentage = (Mass of component of solution/Total mass of solution)×100

Here, Mass of component of solution = 22 g

And Mass of solution = 22 + 122 = 144 g

Hence, Mass percentage of Benzene = (22/144)×100 = 15.28%

And, Mass percentage of CCl4 = (122/144)×100 = 84.72%

Extra Information -

Other different ways of describing the concentration of a solution quantitatively :

• Volume percentage of a component is the percentage of the ratio of volume of the component on total volume of the solution.
• Mass by volume percentage is mass of solute dissolved in 100 ml of solution.
• Parts per million = (Number of parts of component/Total number of parts of all components of the solution)×10⁶
• Mole fraction is the ratio of number of moles of the component on total number of moles of all the components.
• Molarity is defined as the number of moles of a solute dissolved in one litre of solution.
• Molality is defined as the number of moles of the solute per kilogram of the solvent.