Question

Calculate the mass of CaO required for the prooduction of 124g of Ca₃(PO₄) according to the equation
6 CaO + P₄O₁₀ → 2 Ca₃(PO₄)₂

Answer 1

RMM of Calcium = 40 g, Oxygen = 16 g, Phosphorus = 31 g

Molar Mass of Calcium Oxide = 40+16 g

= 56 g

Molar Mass of 6 molecules of Calcium Oxide =56*6 g

= 336 g

Molar Mass of Calcium Phosphate =40*3+2*(31+64) g

= 120+2*95 g

= 310 g

Molar Mass of 2 molecules of Calcium Phosphate = 310*2 g

= 620 g

If 336 g of Calcium Oxide produces 620 g of Calcium Phosphate, 124 g of Calcium Phosphate will need = (336/620)*124 g of Calcium Oxide

= 67.2 g of Calcium Oxide

I hope this helps.