if the radius of the base of a right circular cylinder is halved , keeping the same , what is the ratio of the volume of the reduce cylinder to that of the original cylinder?
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Answer:
The ratio of the volume of the reduced cylinder to that of the original is 1:4
Step-by-step explanation:
Let the radius of cylinder be r
Let the height be h
Volume of cylinder = πr²h
New radius = r/2
Height remains same
New Volume = π(r/2)²h
The ratio of the volume of the reduced cylinder to that of the original :
= π(r/2)²/h
________
πr²h
=1/4
Hence The ratio of the volume of the reduced cylinder to that of the original is 1:4
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