Question

Calculate the mass of carbon dioxide released in the reaction when 6.39 of sodium bicarbonate is added to 15.09 of acetic acid solution and 18.09 of residue l8 left behind. 2.89 of calcium oxide prepared by heating limestone was found to contain 0.8 g of oxygen. When one gram of oxygen was treated with calcium. 3.5 9 of calcium oxide was obtained. Show that the results illustrate the law of definite preponions.

Answer 1

ANSWER

The mass of residue, is CH

3

COONa solution, should be 24g of CH

3

COONa solution.

In this reaction, sodium bicarbonate reacts with acetic acid to produce sodium acetate, carbon dioxide and water

NaHCO

3

+CH

3

COOH⟶CH

3

COONa+CO

2

+H

2

O

According to law of conversation of masses,

total masses of reactants = total masses of products

reactants are 8.4g NaHCO

3

and 20g CH

3

COOH.

total mass of reactants is =28.4g

mass of residue = (28.4g reactants mass) − (4.4g CO

2

)

= 24.0g residue (sodium acetate solution)

mass of residue is thus 24 grams.

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