Question

calculate the mass of chlorine required to react with 0.2 gram of hydrogen to yield HCL .Also calculate the amount of HCL formed......
plz help sis bros

Answer 1

as
H2 + Cl2 == > 2HCl
1 V of H2= 1 V OF CL
SO 0.2 V OF CL WILL BE EQUAL TO 0.2 G OF H2
SO THE AMOUNT OF HCl formed = 2*0.2= 0.4

Answer 2

Answer:

The mass of chlorine required to react with 0.2gm of hydrogen is 7.1gm and the mass of HCl formed is 7.3gm

Explanation:

Given that,

The mass of hydrogen used is 0.2gm.

The chemical reaction of formation of Hydrochloric acid is written below

$H_{2}+Cl_{2}<==>2HCl$

From the above reaction,we can interpret that

2gm of hydrogen reacts with 71g of chlorine to from 73gm of HCl

Therefore,the amount of chlorine which reacts with 0.2gm of hydrogen is

$\frac{0.2}{2} \times 71 = 7.1gm$

And the amount of HCl formed with this hydrogen is

$73 \times \frac{0.2}{2} = 7.3gm$

Therefore,The mass of chlorine required to react with 0.2gm of hydrogen is 7.1gm and the mass of HCl formed is 7.3gm

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