Calculate the mass of copper deposited by CUSO4 by the passage of 0.4A for 3 hours
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Answered by
1
Answer:
1.42g is the right answer.
Explanation:
Refer attachment for explanation!!!
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Answered by
1
Answer:
Explanation:use q=Ixt
t in sec =10800
Q=4320c
Q=(n x f x given mass)/atomic mass
When cu is deposited 2 electrons are need to convert Cu2+ to Cu
Therefore n=2
f=96500
Atomic mass=63.5
Therefore when you substitute in the formula find given mass
mass=4320 x 63.5 /2x 96500
mass of cu =1.42g approx
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