Question

Calculate the mass of ice required to lower the temperature of 300g of water at 40celcius to water at 0celcius

Answer 1

300 grams యాత్ర ముగిసేనాటికి రోజులు

Answer 2

Answer:

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Mass of water =300g

Initial temperature =40°C

Final temperature = 0°C

Let the mass of ice = o g

=300*4.2*(40-0)J

=300*4.2*40 J

=50400J

Heat lost by ice from 40°C to 0°C of water

=o*336

=50400

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o=50400/336

=150 g

hope its helpfull..