factorise it please
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take 7 common
7(a3+8b3)
use the formulae for a3 + b3 i.e. (a+b)(a2+b2+ab)
the ans will come 7((a+2b)(a2+4b2+ 2ab).
7(a3+8b3)
use the formulae for a3 + b3 i.e. (a+b)(a2+b2+ab)
the ans will come 7((a+2b)(a2+4b2+ 2ab).
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Answer- Q. Factorise 7a^3+56b^3 Solution- Taking 7 as common factor, = 7(a^3+8b^3) = 7{(a)^3+ (2b)^3} x^3+ y^3=(x+y) (x^2-xy+ y^2) Here, x= a, y=2y Substituting values, = 7 (a+2b) (a^2-2ab+4b^2) Now, (a^2-2ab+b^2)= (a-b)^2 Here, a= a, b= 2b Again, substituting values, = 7(a+2b)(a-2b)^2 = 7(a+2b)(a-2b)(a-2b) Therefore, 7a^3+56b^3= 7(a+2b)(a-2b)(a-2b). Please Mark as the BRAINLIEST answer if helpful
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